As per our current Database, Matt Buckley is still alive (as per Wikipedia, Last update: May 10, 2020).
Currently, Matt Buckley is 42 years, 8 months and 27 days old. Matt Buckley will celebrate 43rd birthday on a Tuesday 20th of August 2024. Below we countdown to Matt Buckley upcoming birthday.
Popular As | Matt Buckley |
Occupation | YouTube Star |
Age | 42 years old |
Zodiac Sign | Leo |
Born | August 20, 1981 (United States) |
Birthday | August 20 |
Town/City | United States |
Nationality | United States |
Matt Buckley’s zodiac sign is Leo. According to astrologers, people born under the sign of Leo are natural born leaders. They are dramatic, creative, self-confident, dominant and extremely difficult to resist, able to achieve anything they want to in any area of life they commit to. There is a specific strength to a Leo and their "king of the jungle" status. Leo often has many friends for they are generous and loyal. Self-confident and attractive, this is a Sun sign capable of uniting different groups of people and leading them as one towards a shared cause, and their healthy sense of humor makes collaboration with other people even easier.
Matt Buckley was born in the Year of the Rooster. Those born under the Chinese Zodiac sign of the Rooster are practical, resourceful, observant, analytical, straightforward, trusting, honest, perfectionists, neat and conservative. Compatible with Ox or Snake.
YouTube gamer who is known for his Bowlingotter channel. He has gained popularity for his Let's Play videos alongside he and his wife Lissy Peebee's commentary.
He began his YouTube channel on May 5, 2006. He appeared in his first video there on February 22, 2012.
He has helped the Bowlingotter YouTube channel amass more than 80,000 subscribers. One of his most popular videos, "Mortal Kombat X | MAKING LISSY WATCH FATALITIES," has earned more than 400,000 total views.
He was joined on his YouTube channel by his wife, Lissy, in December 2012.
He and fellow YouTuber SwingPoynt are both known for their lively game commentary.